Integrand size = 31, antiderivative size = 124 \[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{\sqrt {a+a \sin (c+d x)}} \, dx=-\frac {152 a^2 \cos ^5(c+d x)}{3465 d (a+a \sin (c+d x))^{5/2}}-\frac {38 a \cos ^5(c+d x)}{693 d (a+a \sin (c+d x))^{3/2}}+\frac {20 \cos ^5(c+d x)}{99 d \sqrt {a+a \sin (c+d x)}}-\frac {2 \cos ^5(c+d x) \sqrt {a+a \sin (c+d x)}}{11 a d} \]
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Time = 0.30 (sec) , antiderivative size = 124, normalized size of antiderivative = 1.00, number of steps used = 5, number of rules used = 4, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.129, Rules used = {2956, 2935, 2753, 2752} \[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{\sqrt {a+a \sin (c+d x)}} \, dx=-\frac {152 a^2 \cos ^5(c+d x)}{3465 d (a \sin (c+d x)+a)^{5/2}}-\frac {2 \cos ^5(c+d x) \sqrt {a \sin (c+d x)+a}}{11 a d}+\frac {20 \cos ^5(c+d x)}{99 d \sqrt {a \sin (c+d x)+a}}-\frac {38 a \cos ^5(c+d x)}{693 d (a \sin (c+d x)+a)^{3/2}} \]
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Rule 2752
Rule 2753
Rule 2935
Rule 2956
Rubi steps \begin{align*} \text {integral}& = \frac {\cos ^5(c+d x)}{4 d \sqrt {a+a \sin (c+d x)}}-\frac {\int \cos ^4(c+d x) \left (-\frac {a}{2}-4 a \sin (c+d x)\right ) \sqrt {a+a \sin (c+d x)} \, dx}{4 a^2} \\ & = \frac {\cos ^5(c+d x)}{4 d \sqrt {a+a \sin (c+d x)}}-\frac {2 \cos ^5(c+d x) \sqrt {a+a \sin (c+d x)}}{11 a d}+\frac {19 \int \cos ^4(c+d x) \sqrt {a+a \sin (c+d x)} \, dx}{88 a} \\ & = \frac {20 \cos ^5(c+d x)}{99 d \sqrt {a+a \sin (c+d x)}}-\frac {2 \cos ^5(c+d x) \sqrt {a+a \sin (c+d x)}}{11 a d}+\frac {19}{99} \int \frac {\cos ^4(c+d x)}{\sqrt {a+a \sin (c+d x)}} \, dx \\ & = -\frac {38 a \cos ^5(c+d x)}{693 d (a+a \sin (c+d x))^{3/2}}+\frac {20 \cos ^5(c+d x)}{99 d \sqrt {a+a \sin (c+d x)}}-\frac {2 \cos ^5(c+d x) \sqrt {a+a \sin (c+d x)}}{11 a d}+\frac {1}{693} (76 a) \int \frac {\cos ^4(c+d x)}{(a+a \sin (c+d x))^{3/2}} \, dx \\ & = -\frac {152 a^2 \cos ^5(c+d x)}{3465 d (a+a \sin (c+d x))^{5/2}}-\frac {38 a \cos ^5(c+d x)}{693 d (a+a \sin (c+d x))^{3/2}}+\frac {20 \cos ^5(c+d x)}{99 d \sqrt {a+a \sin (c+d x)}}-\frac {2 \cos ^5(c+d x) \sqrt {a+a \sin (c+d x)}}{11 a d} \\ \end{align*}
Time = 2.11 (sec) , antiderivative size = 143, normalized size of antiderivative = 1.15 \[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{\sqrt {a+a \sin (c+d x)}} \, dx=-\frac {\left (\cos \left (\frac {1}{2} (c+d x)\right )-\sin \left (\frac {1}{2} (c+d x)\right )\right )^5 \left (5773 \cos \left (\frac {1}{2} (c+d x)\right )-3495 \cos \left (\frac {3}{2} (c+d x)\right )-1505 \cos \left (\frac {5}{2} (c+d x)\right )+315 \cos \left (\frac {7}{2} (c+d x)\right )+5773 \sin \left (\frac {1}{2} (c+d x)\right )+3495 \sin \left (\frac {3}{2} (c+d x)\right )-1505 \sin \left (\frac {5}{2} (c+d x)\right )-315 \sin \left (\frac {7}{2} (c+d x)\right )\right )}{13860 d \sqrt {a (1+\sin (c+d x))}} \]
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Time = 0.10 (sec) , antiderivative size = 74, normalized size of antiderivative = 0.60
method | result | size |
default | \(\frac {2 \left (1+\sin \left (d x +c \right )\right ) \left (\sin \left (d x +c \right )-1\right )^{3} \left (315 \left (\sin ^{3}\left (d x +c \right )\right )+595 \left (\sin ^{2}\left (d x +c \right )\right )+340 \sin \left (d x +c \right )+136\right )}{3465 \cos \left (d x +c \right ) \sqrt {a +a \sin \left (d x +c \right )}\, d}\) | \(74\) |
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Time = 0.28 (sec) , antiderivative size = 155, normalized size of antiderivative = 1.25 \[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{\sqrt {a+a \sin (c+d x)}} \, dx=-\frac {2 \, {\left (315 \, \cos \left (d x + c\right )^{6} - 35 \, \cos \left (d x + c\right )^{5} - 445 \, \cos \left (d x + c\right )^{4} + 19 \, \cos \left (d x + c\right )^{3} - 38 \, \cos \left (d x + c\right )^{2} + {\left (315 \, \cos \left (d x + c\right )^{5} + 350 \, \cos \left (d x + c\right )^{4} - 95 \, \cos \left (d x + c\right )^{3} - 114 \, \cos \left (d x + c\right )^{2} - 152 \, \cos \left (d x + c\right ) - 304\right )} \sin \left (d x + c\right ) + 152 \, \cos \left (d x + c\right ) + 304\right )} \sqrt {a \sin \left (d x + c\right ) + a}}{3465 \, {\left (a d \cos \left (d x + c\right ) + a d \sin \left (d x + c\right ) + a d\right )}} \]
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\[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{\sqrt {a+a \sin (c+d x)}} \, dx=\int \frac {\sin ^{2}{\left (c + d x \right )} \cos ^{4}{\left (c + d x \right )}}{\sqrt {a \left (\sin {\left (c + d x \right )} + 1\right )}}\, dx \]
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\[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{\sqrt {a+a \sin (c+d x)}} \, dx=\int { \frac {\cos \left (d x + c\right )^{4} \sin \left (d x + c\right )^{2}}{\sqrt {a \sin \left (d x + c\right ) + a}} \,d x } \]
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Time = 0.29 (sec) , antiderivative size = 103, normalized size of antiderivative = 0.83 \[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{\sqrt {a+a \sin (c+d x)}} \, dx=-\frac {16 \, \sqrt {2} {\left (1260 \, \sqrt {a} \sin \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{11} - 3080 \, \sqrt {a} \sin \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{9} + 2475 \, \sqrt {a} \sin \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{7} - 693 \, \sqrt {a} \sin \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )^{5}\right )}}{3465 \, a d \mathrm {sgn}\left (\cos \left (-\frac {1}{4} \, \pi + \frac {1}{2} \, d x + \frac {1}{2} \, c\right )\right )} \]
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Timed out. \[ \int \frac {\cos ^4(c+d x) \sin ^2(c+d x)}{\sqrt {a+a \sin (c+d x)}} \, dx=\int \frac {{\cos \left (c+d\,x\right )}^4\,{\sin \left (c+d\,x\right )}^2}{\sqrt {a+a\,\sin \left (c+d\,x\right )}} \,d x \]
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